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Going over each step in detail: >x * (-y) = (x * (-y) + x * y) - x * y by lemma 1 >x * ((-y) + y) - x * y = x * 0 - x * y we replace (-y) + y with 0 by lemma 2 >x * 0 - x * y = 0 - x * y we replace x * 0 with 0 by lemma 3 >0 - x * y = -(x * y) "0 - x * y" is shorthand for "0 + -(x * y)", and 0 is the additive identity.

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